3.2043 \(\int \frac {1}{\sqrt {1-2 x} (2+3 x)^2 (3+5 x)} \, dx\)

Optimal. Leaf size=77 \[ \frac {3 \sqrt {1-2 x}}{7 (3 x+2)}+\frac {72}{7} \sqrt {\frac {3}{7}} \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )-10 \sqrt {\frac {5}{11}} \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right ) \]

[Out]

72/49*arctanh(1/7*21^(1/2)*(1-2*x)^(1/2))*21^(1/2)-10/11*arctanh(1/11*55^(1/2)*(1-2*x)^(1/2))*55^(1/2)+3/7*(1-
2*x)^(1/2)/(2+3*x)

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Rubi [A]  time = 0.03, antiderivative size = 77, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {103, 156, 63, 206} \[ \frac {3 \sqrt {1-2 x}}{7 (3 x+2)}+\frac {72}{7} \sqrt {\frac {3}{7}} \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )-10 \sqrt {\frac {5}{11}} \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right ) \]

Antiderivative was successfully verified.

[In]

Int[1/(Sqrt[1 - 2*x]*(2 + 3*x)^2*(3 + 5*x)),x]

[Out]

(3*Sqrt[1 - 2*x])/(7*(2 + 3*x)) + (72*Sqrt[3/7]*ArcTanh[Sqrt[3/7]*Sqrt[1 - 2*x]])/7 - 10*Sqrt[5/11]*ArcTanh[Sq
rt[5/11]*Sqrt[1 - 2*x]]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 103

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(b*(a +
b*x)^(m + 1)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/((m + 1)*(b*c - a*d)*(b*e - a*f)), x] + Dist[1/((m + 1)*(b*
c - a*d)*(b*e - a*f)), Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p*Simp[a*d*f*(m + 1) - b*(d*e*(m + n + 2) +
c*f*(m + p + 2)) - b*d*f*(m + n + p + 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && LtQ[m, -1] &&
IntegerQ[m] && (IntegerQ[n] || IntegersQ[2*n, 2*p])

Rule 156

Int[(((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)))/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))), x_Symbol] :>
Dist[(b*g - a*h)/(b*c - a*d), Int[(e + f*x)^p/(a + b*x), x], x] - Dist[(d*g - c*h)/(b*c - a*d), Int[(e + f*x)
^p/(c + d*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, h}, x]

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin {align*} \int \frac {1}{\sqrt {1-2 x} (2+3 x)^2 (3+5 x)} \, dx &=\frac {3 \sqrt {1-2 x}}{7 (2+3 x)}+\frac {1}{7} \int \frac {26-15 x}{\sqrt {1-2 x} (2+3 x) (3+5 x)} \, dx\\ &=\frac {3 \sqrt {1-2 x}}{7 (2+3 x)}-\frac {108}{7} \int \frac {1}{\sqrt {1-2 x} (2+3 x)} \, dx+25 \int \frac {1}{\sqrt {1-2 x} (3+5 x)} \, dx\\ &=\frac {3 \sqrt {1-2 x}}{7 (2+3 x)}+\frac {108}{7} \operatorname {Subst}\left (\int \frac {1}{\frac {7}{2}-\frac {3 x^2}{2}} \, dx,x,\sqrt {1-2 x}\right )-25 \operatorname {Subst}\left (\int \frac {1}{\frac {11}{2}-\frac {5 x^2}{2}} \, dx,x,\sqrt {1-2 x}\right )\\ &=\frac {3 \sqrt {1-2 x}}{7 (2+3 x)}+\frac {72}{7} \sqrt {\frac {3}{7}} \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )-10 \sqrt {\frac {5}{11}} \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right )\\ \end {align*}

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Mathematica [A]  time = 0.07, size = 77, normalized size = 1.00 \[ \frac {3 \sqrt {1-2 x}}{7 (3 x+2)}+\frac {72}{7} \sqrt {\frac {3}{7}} \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )-10 \sqrt {\frac {5}{11}} \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[1/(Sqrt[1 - 2*x]*(2 + 3*x)^2*(3 + 5*x)),x]

[Out]

(3*Sqrt[1 - 2*x])/(7*(2 + 3*x)) + (72*Sqrt[3/7]*ArcTanh[Sqrt[3/7]*Sqrt[1 - 2*x]])/7 - 10*Sqrt[5/11]*ArcTanh[Sq
rt[5/11]*Sqrt[1 - 2*x]]

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fricas [A]  time = 1.08, size = 102, normalized size = 1.32 \[ \frac {245 \, \sqrt {11} \sqrt {5} {\left (3 \, x + 2\right )} \log \left (\frac {\sqrt {11} \sqrt {5} \sqrt {-2 \, x + 1} + 5 \, x - 8}{5 \, x + 3}\right ) + 396 \, \sqrt {7} \sqrt {3} {\left (3 \, x + 2\right )} \log \left (-\frac {\sqrt {7} \sqrt {3} \sqrt {-2 \, x + 1} - 3 \, x + 5}{3 \, x + 2}\right ) + 231 \, \sqrt {-2 \, x + 1}}{539 \, {\left (3 \, x + 2\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(2+3*x)^2/(3+5*x)/(1-2*x)^(1/2),x, algorithm="fricas")

[Out]

1/539*(245*sqrt(11)*sqrt(5)*(3*x + 2)*log((sqrt(11)*sqrt(5)*sqrt(-2*x + 1) + 5*x - 8)/(5*x + 3)) + 396*sqrt(7)
*sqrt(3)*(3*x + 2)*log(-(sqrt(7)*sqrt(3)*sqrt(-2*x + 1) - 3*x + 5)/(3*x + 2)) + 231*sqrt(-2*x + 1))/(3*x + 2)

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giac [A]  time = 1.19, size = 95, normalized size = 1.23 \[ \frac {5}{11} \, \sqrt {55} \log \left (\frac {{\left | -2 \, \sqrt {55} + 10 \, \sqrt {-2 \, x + 1} \right |}}{2 \, {\left (\sqrt {55} + 5 \, \sqrt {-2 \, x + 1}\right )}}\right ) - \frac {36}{49} \, \sqrt {21} \log \left (\frac {{\left | -2 \, \sqrt {21} + 6 \, \sqrt {-2 \, x + 1} \right |}}{2 \, {\left (\sqrt {21} + 3 \, \sqrt {-2 \, x + 1}\right )}}\right ) + \frac {3 \, \sqrt {-2 \, x + 1}}{7 \, {\left (3 \, x + 2\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(2+3*x)^2/(3+5*x)/(1-2*x)^(1/2),x, algorithm="giac")

[Out]

5/11*sqrt(55)*log(1/2*abs(-2*sqrt(55) + 10*sqrt(-2*x + 1))/(sqrt(55) + 5*sqrt(-2*x + 1))) - 36/49*sqrt(21)*log
(1/2*abs(-2*sqrt(21) + 6*sqrt(-2*x + 1))/(sqrt(21) + 3*sqrt(-2*x + 1))) + 3/7*sqrt(-2*x + 1)/(3*x + 2)

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maple [A]  time = 0.01, size = 54, normalized size = 0.70 \[ \frac {72 \sqrt {21}\, \arctanh \left (\frac {\sqrt {21}\, \sqrt {-2 x +1}}{7}\right )}{49}-\frac {10 \sqrt {55}\, \arctanh \left (\frac {\sqrt {55}\, \sqrt {-2 x +1}}{11}\right )}{11}-\frac {2 \sqrt {-2 x +1}}{7 \left (-2 x -\frac {4}{3}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(3*x+2)^2/(5*x+3)/(-2*x+1)^(1/2),x)

[Out]

-10/11*arctanh(1/11*55^(1/2)*(-2*x+1)^(1/2))*55^(1/2)-2/7*(-2*x+1)^(1/2)/(-2*x-4/3)+72/49*arctanh(1/7*21^(1/2)
*(-2*x+1)^(1/2))*21^(1/2)

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maxima [A]  time = 1.28, size = 89, normalized size = 1.16 \[ \frac {5}{11} \, \sqrt {55} \log \left (-\frac {\sqrt {55} - 5 \, \sqrt {-2 \, x + 1}}{\sqrt {55} + 5 \, \sqrt {-2 \, x + 1}}\right ) - \frac {36}{49} \, \sqrt {21} \log \left (-\frac {\sqrt {21} - 3 \, \sqrt {-2 \, x + 1}}{\sqrt {21} + 3 \, \sqrt {-2 \, x + 1}}\right ) + \frac {3 \, \sqrt {-2 \, x + 1}}{7 \, {\left (3 \, x + 2\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(2+3*x)^2/(3+5*x)/(1-2*x)^(1/2),x, algorithm="maxima")

[Out]

5/11*sqrt(55)*log(-(sqrt(55) - 5*sqrt(-2*x + 1))/(sqrt(55) + 5*sqrt(-2*x + 1))) - 36/49*sqrt(21)*log(-(sqrt(21
) - 3*sqrt(-2*x + 1))/(sqrt(21) + 3*sqrt(-2*x + 1))) + 3/7*sqrt(-2*x + 1)/(3*x + 2)

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mupad [B]  time = 0.10, size = 53, normalized size = 0.69 \[ \frac {72\,\sqrt {21}\,\mathrm {atanh}\left (\frac {\sqrt {21}\,\sqrt {1-2\,x}}{7}\right )}{49}-\frac {10\,\sqrt {55}\,\mathrm {atanh}\left (\frac {\sqrt {55}\,\sqrt {1-2\,x}}{11}\right )}{11}+\frac {2\,\sqrt {1-2\,x}}{7\,\left (2\,x+\frac {4}{3}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/((1 - 2*x)^(1/2)*(3*x + 2)^2*(5*x + 3)),x)

[Out]

(72*21^(1/2)*atanh((21^(1/2)*(1 - 2*x)^(1/2))/7))/49 - (10*55^(1/2)*atanh((55^(1/2)*(1 - 2*x)^(1/2))/11))/11 +
(2*(1 - 2*x)^(1/2))/(7*(2*x + 4/3))

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sympy [C]  time = 11.53, size = 534, normalized size = 6.94 \[ \frac {2940 \sqrt {55} \left (x - \frac {1}{2}\right )^{\frac {3}{2}} \operatorname {atan}{\left (\frac {\sqrt {110} \sqrt {x - \frac {1}{2}}}{11} \right )}}{3234 i \left (x - \frac {1}{2}\right )^{\frac {3}{2}} + 3773 i \sqrt {x - \frac {1}{2}}} - \frac {132 \sqrt {21} \left (x - \frac {1}{2}\right )^{\frac {3}{2}} \operatorname {atan}{\left (\frac {\sqrt {42}}{6 \sqrt {x - \frac {1}{2}}} \right )}}{3234 i \left (x - \frac {1}{2}\right )^{\frac {3}{2}} + 3773 i \sqrt {x - \frac {1}{2}}} - \frac {4884 \sqrt {21} \left (x - \frac {1}{2}\right )^{\frac {3}{2}} \operatorname {atan}{\left (\frac {\sqrt {42} \sqrt {x - \frac {1}{2}}}{7} \right )}}{3234 i \left (x - \frac {1}{2}\right )^{\frac {3}{2}} + 3773 i \sqrt {x - \frac {1}{2}}} - \frac {1470 \sqrt {55} \pi \left (x - \frac {1}{2}\right )^{\frac {3}{2}}}{3234 i \left (x - \frac {1}{2}\right )^{\frac {3}{2}} + 3773 i \sqrt {x - \frac {1}{2}}} + \frac {2442 \sqrt {21} \pi \left (x - \frac {1}{2}\right )^{\frac {3}{2}}}{3234 i \left (x - \frac {1}{2}\right )^{\frac {3}{2}} + 3773 i \sqrt {x - \frac {1}{2}}} + \frac {3430 \sqrt {55} \sqrt {x - \frac {1}{2}} \operatorname {atan}{\left (\frac {\sqrt {110} \sqrt {x - \frac {1}{2}}}{11} \right )}}{3234 i \left (x - \frac {1}{2}\right )^{\frac {3}{2}} + 3773 i \sqrt {x - \frac {1}{2}}} - \frac {154 \sqrt {21} \sqrt {x - \frac {1}{2}} \operatorname {atan}{\left (\frac {\sqrt {42}}{6 \sqrt {x - \frac {1}{2}}} \right )}}{3234 i \left (x - \frac {1}{2}\right )^{\frac {3}{2}} + 3773 i \sqrt {x - \frac {1}{2}}} - \frac {5698 \sqrt {21} \sqrt {x - \frac {1}{2}} \operatorname {atan}{\left (\frac {\sqrt {42} \sqrt {x - \frac {1}{2}}}{7} \right )}}{3234 i \left (x - \frac {1}{2}\right )^{\frac {3}{2}} + 3773 i \sqrt {x - \frac {1}{2}}} - \frac {1715 \sqrt {55} \pi \sqrt {x - \frac {1}{2}}}{3234 i \left (x - \frac {1}{2}\right )^{\frac {3}{2}} + 3773 i \sqrt {x - \frac {1}{2}}} + \frac {2849 \sqrt {21} \pi \sqrt {x - \frac {1}{2}}}{3234 i \left (x - \frac {1}{2}\right )^{\frac {3}{2}} + 3773 i \sqrt {x - \frac {1}{2}}} - \frac {462 \sqrt {2} \left (x - \frac {1}{2}\right )}{3234 i \left (x - \frac {1}{2}\right )^{\frac {3}{2}} + 3773 i \sqrt {x - \frac {1}{2}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(2+3*x)**2/(3+5*x)/(1-2*x)**(1/2),x)

[Out]

2940*sqrt(55)*(x - 1/2)**(3/2)*atan(sqrt(110)*sqrt(x - 1/2)/11)/(3234*I*(x - 1/2)**(3/2) + 3773*I*sqrt(x - 1/2
)) - 132*sqrt(21)*(x - 1/2)**(3/2)*atan(sqrt(42)/(6*sqrt(x - 1/2)))/(3234*I*(x - 1/2)**(3/2) + 3773*I*sqrt(x -
1/2)) - 4884*sqrt(21)*(x - 1/2)**(3/2)*atan(sqrt(42)*sqrt(x - 1/2)/7)/(3234*I*(x - 1/2)**(3/2) + 3773*I*sqrt(
x - 1/2)) - 1470*sqrt(55)*pi*(x - 1/2)**(3/2)/(3234*I*(x - 1/2)**(3/2) + 3773*I*sqrt(x - 1/2)) + 2442*sqrt(21)
*pi*(x - 1/2)**(3/2)/(3234*I*(x - 1/2)**(3/2) + 3773*I*sqrt(x - 1/2)) + 3430*sqrt(55)*sqrt(x - 1/2)*atan(sqrt(
110)*sqrt(x - 1/2)/11)/(3234*I*(x - 1/2)**(3/2) + 3773*I*sqrt(x - 1/2)) - 154*sqrt(21)*sqrt(x - 1/2)*atan(sqrt
(42)/(6*sqrt(x - 1/2)))/(3234*I*(x - 1/2)**(3/2) + 3773*I*sqrt(x - 1/2)) - 5698*sqrt(21)*sqrt(x - 1/2)*atan(sq
rt(42)*sqrt(x - 1/2)/7)/(3234*I*(x - 1/2)**(3/2) + 3773*I*sqrt(x - 1/2)) - 1715*sqrt(55)*pi*sqrt(x - 1/2)/(323
4*I*(x - 1/2)**(3/2) + 3773*I*sqrt(x - 1/2)) + 2849*sqrt(21)*pi*sqrt(x - 1/2)/(3234*I*(x - 1/2)**(3/2) + 3773*
I*sqrt(x - 1/2)) - 462*sqrt(2)*(x - 1/2)/(3234*I*(x - 1/2)**(3/2) + 3773*I*sqrt(x - 1/2))

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